Step-by-step explanation:
It is given that,
Mass of the artillery shell, m = 1100 kg
Acceleration of he shell,

(a) The magnitude of force exerted on the shell can be calculated using Newton's second law of motion as :
F = ma

F = 26400000 N
or

(b) The magnitude of the force exerted on the ship by the artillery shell will be same but the direction is opposite as per Newton's third law of motion. i.e