183k views
0 votes
(a) What net external force is exerted on a 1100.0-kg artillery shell fired from a battleship if the shell is accelerated at 2.40 × 10 4 m/s 2 ? (b) What is the magnitude of the force exerted on the ship by the artillery shell, and why?

User Joey Trang
by
6.2k points

1 Answer

3 votes

Step-by-step explanation:

It is given that,

Mass of the artillery shell, m = 1100 kg

Acceleration of he shell,
a=2.4* 10^4\ m/s^2

(a) The magnitude of force exerted on the shell can be calculated using Newton's second law of motion as :

F = ma


F=1100\ kg* 2.4* 10^4\ m/s^2

F = 26400000 N

or


F=2.6* 10^7\ N

(b) The magnitude of the force exerted on the ship by the artillery shell will be same but the direction is opposite as per Newton's third law of motion. i.e
2.6* 10^7\ N

User Jaaksarv
by
5.8k points