Question

A 1.83 kg1.83 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.5220.522 and the coefficient of kinetic friction is 0.2830.283 . How much force is needed to begin moving the book?

Answer 1

9.4 N

Step-by-step explanation:

m = mass of the book = 1.83 kg

`\mu _(s)` = Coefficient of static friction = 0.522

`\mu _(k)` = Coefficient of kinetic friction = 0.283

`f_(s)` = Static frictional force

F = force needed to make the book move

force needed to make the book move is same as the magnitude of maximum static frictional force applied by the desk on the book

Static frictional force is given as

`f_(s)` =
`\mu _(s)` mg

Hence, the force need to move the book is given as

F =
`f_(s)` =
`\mu _(s)` mg

F =
`\mu _(s)` mg

F = (0.522) (1.83 x 9.8)

F = 9.4 N