Final answer:
The osmotic pressure of a 0.82% NaCl solution at 36°C is 34 atm.
Step-by-step explanation:
The osmotic pressure of a solution can be calculated using the formula II = MRT, where II is the osmotic pressure, M is the molarity of the solution, R is the ideal gas constant, and T is the temperature in Kelvin.
In this case, the molarity of the solution is 0.70 M NaCl. Since 1 mol of NaCl produces 2 mol of particles, the total concentration of dissolved particles is (2)(0.70 M) = 1.4 M.
Plugging in the values into the formula, II = (1.4 mol/L) [0.0821 (L· atm)/(K · mol)] (298 K) = 34 atm.