Answer:
Explanation:
Your "y=2xsquared-12x+10" translates into y = 2x^2 - 12x + 10. This factors into y = 2(x^2 - 6x + 5).
Setting this = to 0 results in y = 2(x - 5)(x - 1) = 0, so that the x-intercepts are (5, 0) and (1, 0). The x-coordinate of the vertex lies halfway between x = 1 and x = 5, that is, at x = 3. Using synthetic division to evaluate y = 2x^2 - 12x + 10 at x = 3, we get
3 2 -12 10
6 -18
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2 -6 -8
Therefore, the vertex is located at (3, -8).
Setting x = 0 results in the y-intercept: y = 2(0)^2 - 12(0) + 10 => (0, 10)