At time t0 = 0 the mass happens to be at y0 = 4.05 cm and moving upward at velocity v0 = +4.12 m/s. (Mind the units!) Calculate the amplitude A of the oscillating mass. Answer i…

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asked Dec 14, 2020 139k views

1 Answer

Bonney · Answer 1 · 2020-12-21T00:06:21+0000

Answer:

A = 5.727 cm

Step-by-step explanation:

at time t = 0s the displacement of mass is 4.05 cm and velocity 4.12 m/s

we know that velcoity for simple harmonic motion is given as

$v_o = \omega \sqrt {A^2 - Y_O^2}$

W KNOW THAT

$\omega = (v_0)/(Y_o)$

Therefore we get

Y_O^2 = A^2 - Y_O^2

$A =\sqrt 2 * Y_O$

$A =\sqrt 2 * 4.05\\$

A = 5.727 cm