Question

At time t0 = 0 the mass happens to be at y0 = 4.05 cm and moving upward at velocity v0 = +4.12 m/s. (Mind the units!) Calculate the amplitude A of the oscillating mass. Answer in units of cm.

Answer 1

A = 5.727 cm

Step-by-step explanation:

at time t = 0s the displacement of mass is 4.05 cm and velocity 4.12 m/s

we know that velcoity for simple harmonic motion is given as

`v_o = \omega \sqrt {A^2 - Y_O^2}`

W KNOW THAT

`\omega = (v_0)/(Y_o)`

Therefore we get

`Y_O^2 = A^2 - Y_O^2`

`A =\sqrt 2 * Y_O`

`A =\sqrt 2 * 4.05\\`

A = 5.727 cm