Answer:
1.06 mL of toluene will be needed.
Step-by-step explanation:
Equi-molar mixture means equal moles of all the components.
as given the volume of ethyl acetate = 1mL
Density of ethyl acetate = 0.898 g/mL
The relation between density, mass and volume is :
![density=(mass)/(volume)](https://img.qammunity.org/2020/formulas/physics/middle-school/t3tsop0rpdnq7bxrlzlf2g7x1a3w07j6ti.png)
mass=volumeXdensity
mass of ethyl acetate present = 1mL X 0.898g/mL = 0.598 grams
the moles are related to mass as:
![moles=(mass)/(molarmass)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/a62h1fc7grch2xlqkjf7czeufmua398pg9.png)
For ethyl acetate molar mass = 4X12+8X1+2X16= 88g/mol
moles of ethyl acetate will be:
![moles=(0.898)/(88)= 0.01mol](https://img.qammunity.org/2020/formulas/chemistry/college/m99x9mh8940l8t1yhrlhczm213yw4apot6.png)
So we need 0.01 moles of toluene also
For 0.01 moles the mass of toluene required = 0.01 X molar mass of toluene
mass required = 0.01 X 92=0.92grams
for 0.92 grams of toluene volume required will be:
![volume=(mass)/(density)=(0.92)/(0.867)= 1.06mL](https://img.qammunity.org/2020/formulas/chemistry/college/13o5aq4xg51qxjtlxc5wh6rs0rfa2s2nk9.png)