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A batter hits a baseball into the air. The formula y=-16x^2+64x+5models the baseball’s height above the ground, y, in feet, x seconds after it is hit.When does the baseball reach its maximum height? What is that height?

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3 votes

Answer:

wow

Step-by-step explanation:

User Bezz
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2 votes

Step-by-step explanation:

A batter hits a baseball into the air. The formula that models the baseball’s height above the ground, y, in feet, x seconds after it is hit is given by :


y=-16x^2+64x+5.........(1)

(a) We need to find the maximum height reached by the baseball. The maximum height reached is calculated by differentiating equation (1) wrt x as :


(dy)/(dx)=0


(d(-16x^2+64x+5))/(dx)=0


-32x+64=0

x = 2 seconds

(b) The height of the ball is given by equation (1) and putting the value of x in it as :


y=-16(2)^2+64(2)+5

y = 69 feets

So, at 2 seconds the baseball reaches its maximum height and its maximum height is 69 feets.

User Lovey
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