Question

A light ray incident on a block of glass makes an incident angle of 50.0° with the normal to the surface. The refracted ray in the block makes an 27.7° with the normal. What is the index of refraction of the glass?

Answer 1

`n_(glass) = 1.65`

Step-by-step explanation:

As we know that the angle of incidence is given as

`i = 50.0^o`

also we have angle of refraction as

`r = 27.7^o`

now by Snell's law we know that

`n_(air) sin i = n_(glass) sin r`

`1 sin50 = n_(glass) sin 27.7`

now we have

`n_(glass) = (sin 50)/(sin 27.7)`

`n_(glass) = 1.65`