Question

A hydrogen molecule (diameter 1.38 × 10-8 cm), traveling at the rms speed, escapes from a 4200 K furnace into a chamber containing cold argon atoms (diameter 3.43 × 10-8 cm) at a density of 4.43 × 1019 atoms/cm3(a) What is the speed of the hydrogen molecule

Answer 1

Answer: The speed of hydrogen molecule is
`7.199* 10^3m/s`

Step-by-step explanation:

The equation used to calculate the root mean square speed of a molecule is:

`V_(rms)=\sqrt{(3RT)/(M)}`

where,

`V_(rms)` = root mean square speed of the molecule = ?

R = Gas constant = 8.314 J/mol.K

T = temperature = 4200 K

M = molar mass of hydrogen molecule =
`2.02g=2.02* 10^(-3)kg` (Conversion factor: 1 kg = 1000 g)

Putting values in above equation, we get:

`V_(rms)=\sqrt{(3* 8.314* 4200)/(2.02* 10^(-3))}\\\\V_(rms)=7.199* 10^3m/s`

Hence, the speed of hydrogen molecule is
`7.199* 10^3m/s`