Question

g A ray of light is incident on a flat reflecting surface and is reflected. If the incident ray makes an angle of 28.7° with the normal to the reflecting surface, what angle does the reflected ray make with the normal?

Answer 1

`\theta_2 = 15.8`degree

Step-by-step explanation:

given data:

`\theta_1 = 28.7 degree`

accoding to the snell's law

`n_1*sin\theta_1=n_2*sin\theta_2`

where n1 is refracting index of air = 1

n2 is refracting index of glass = 1.55

putting all value to get angle mad by incident ray with normal

`\theta_2 = (1*sin28.7^(o))/(1.55)`

`\theta_2 = 15.8`degree