Question

A thin coil has 16 rectangular turns of wire. When a current of 3 A runs through the coil, there is a total flux of 4 × 10-3 T·m2 enclosed by one turn of the coil (note that , and you can calculate the proportionality constant ). Determine the inductance in henries.

Answer 1

The inductance is 0.021 H.

Step-by-step explanation:

Given that,

Number of turns = 16

Current = 3 A

Total flux
`\phi=4*10^(-3)\ Tm^2`

We need to calculate the inductance

Using formula of total flux

`N\phi = Li`

`L=(N\phi)/(i)`

Where, i = current

N = number of turns

`\phi` = flux

Put the value into the formula

`L=(16*4*10^(-3))/(3)`

`L=0.021\ H`

Hence, The inductance is 0.021 H.