Question

A box of mass 8 kg slides across a frictionless surface at an initial speed 1.5 m/s into a relaxed spring of spring constant 69 N/m. How long is the box in contact with the spring before it bounces off in the opposite direction?

Answer 1

1.1 sec

Step-by-step explanation:

m = mass of the box = 8 kg

k = spring constant of the spring = 69 N/m

v = initial speed of the box = 1.5 m/s

t = time period of oscillation of box in contact with the spring

Time period is given as

`t = \pi \sqrt{(m)/(k)}`

Inserting the values

`t = (3.14) \sqrt{(8)/(69)}`

t = 1.1 sec