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In reverse osmosis, water flows out of a salt solution until the osmotic pressure of the solution equals the applied pressure. If a pressure of 70.0 bar is applied to seawater, what will be the final concentration of the seawater at 20 ∘C when reverse osmosis stops?

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Answer : The final concentration of the seawater is, 2.909 mole/L

Explanation :

Formula used for osmotic pressure :


\pi=CRT

where,


\pi = osmotic pressure = 70.0 bar = 70 atm

R = solution constant = 0.0821 Latm/moleK

T= temperature of solution =
20^oC=273+20=293K

C = final concentration of seawater = ?

Now put all the given values in the above formula, we get the concentration of seawater.


70atm=C* 0.0821Latm/moleK* 293K


C=2.909mole/L

Therefore, the final concentration of the seawater is, 2.909 mole/L

User Leif Arne Storset
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