Question

An LC circuit consists of a 3.14 mH inductor and a 5.08 µF capacitor. (a) Find its impedance at 55.7 Hz. 563.57 Correct: Your answer is correct. Ω (b) Find its impedance at 11.0 kHz.

Answer 1

a)

`z=561.7`

b)

`z=214.1`

Step-by-step explanation:

L = inductance of the Inductor = 3.14 mH = 0.00314 H

C = capacitance of the capacitor = 5.08 x 10⁻⁶ F

a)

f = frequency = 55.7 Hz

Impedance is given as

`z=(1)/(2\pi fC) - 2\pi fL`

`z=(1)/(2(3.14) (55.7)(5.08* 10^(-6))) - 2(3.14) (55.7)(0.00314)`

`z=561.7`

b)

f = frequency = 11000 Hz

Impedance is given as

`z= - (1)/(2\pi fC) + 2\pi fL`

`z= - (1)/(2(3.14) (11000)(5.08* 10^(-6))) + 2(3.14) (11000)(0.00314)`

`z=214.1`