Question

two cars are traveling down the highway with the same speed. if the first car increases its speed by 1 km per hour and the other car decreases its speed by 10 km per hour then the first car will cover the same distance in 2 hours as a second car in 3 hours what is the speed of the cars​

Answer 1

original speed = 32 km/h

Explanation:

The distance, d, is equal for both cars.

Original speed of both cars = s.

New speed of first car: s + 1

New speed of second car: s - 10

Time for first car = 2

Time for second car = 3

speed = distance/time

distance = speed × time

d = st

First car:

d = st

d = (s + 1) × 2

Second car:

d = st

d = (s - 10) × 3

The distances are equal.

2(s + 1) = 3(s - 10)

2s + 2 = 3s - 30

-s = -32

s = 32

Original speed = 32 km/h