Answer:
50.4 Hz
Step-by-step explanation:
A = amplitude of the wave = 5 cm = 0.05 m
μ = linear mass density = 0.04 kg/m
P = maximum power delivered by source = 275 Watt
T = tension force in the string = 121 N
Speed of the wave is given as
![v=\sqrt{(T)/(\mu )}](https://img.qammunity.org/2020/formulas/physics/college/osad8t3xxsofswk6fcg1lta6h2jwsk2wpu.png)
![v=\sqrt{(121)/(0.04 )}](https://img.qammunity.org/2020/formulas/physics/college/g6ekb8d2ojycjqqe5stilm1e74fqjn8fua.png)
= 55 m/s
maximum power is given as
![P = (\mu (2\pi f)^(2) A^(2)v)/(2)](https://img.qammunity.org/2020/formulas/physics/college/m0nf72o0dnzescwg3giw8a83g9w6125x77.png)
![275 = ((0.04) (2(3.14) f)^(2) (0.05)^(2)(55))/(2)](https://img.qammunity.org/2020/formulas/physics/college/u0qnx2mp7a6rp6btb1150mc70zyet1ffnk.png)
= 50.4 Hz