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Find three consecutive odd integers for which the sum of the first and the second is equal to nine more than the third.

1 Answer

2 votes

Answer:

11, 13, 15

Explanation:

Let x represent the middle of the three integers.

(x -2) +x = (x +2) +9 . . . . the given relation

2x -2 = x +11 . . . . simplify

x = 13 . . . . . add 2-x

The integers are 11, 13, 15.

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