Question

When the function f(x) = 6(9)" is changed to fix) = 6(9)*+1, what is the effect?

There is no change to the graph because the exponential portion of the function remains the same
All input values are moved one space to the right
The x-intercept is one space higher.
The y-intercept is one space higher.

Answer 1

The y-intercept is one space higher.

Explanation:

Answer 2

The y-intercept is one space higher

Explanation:

Remember that the y-intercept is the value of y when the value of x is equal to zero (initial value)

we have

`f(x)=6(9^(x))`

For x=0

`f(0)=6(9^(0))=6` ----> y-intercept

If the function is changed to

`f(x)=6(9^(x))+1`

For x=0

`f(0)=6(9^(0))+1=7` ---> y-intercept

therefore

The y-intercept is one space higher