Question

Which of the following is the equation of the line that is perpendicular to y = -1/8x-2 and goes through the point (-2,-3)?

Answer 1

y=8x+13

Explanation:

Perpendicular Lines are those with the following condition:

y=a*x+b (1)

y=c*x+d (2)

Where 'a' and 'c' are the respective slope

If These two lines are perpendicular, then

a=- 1/c

Equation (1) for our case is written as y=-(1/8)x-2, meaning that a=-1/8 and b = 2

Using those principles we have that the slope for our needed line ('c') has to be 8.

Now we most use the given point to find the remaining term of the equation (d)

Evaluate it in eq (2) to have this:

-3=8*(-2)+d

resulting that d=13