Question

Perform the indicated operation.
3k+6/(k-2)+(2-k)= answers::: 3, -3,3k+6/k-2,3k+6/k+2

Answer 1

3 is the correct option.

Explanation:

The given expression is:

3k+6/(k-2)+(2-k)

Break the numerators:

3k/(k-2) + 6/(2-k)

Now Re-arrange the term (2-k) in the denominator as (-k+2)

3k/(k-2) + 6/(-k+2)

Now takeout -1 as a common factor from (-k+2)

3k/(k-2) + 6/-1(k-2)

Now move a negative (-1)from the denominator of 6/-1(k-2) to the numerator

3k/(k-2) + -1*6/(k-2)

Now take the L.C.M of the denominator which is k-2 and solve the numerator

3k - 6/ (k-2)

Take 3 as a common factor from the numerator:

3(k-2)/(k-2)

k-2 will be cancelled out by each other:

Thus the answer will be 3.

The correct option is 3....