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4. What is the electric field strength (E) at a distance of 0.50 m from a 1.00×10°C charge?

User Dln
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1 Answer

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Answer:

3.6*10¹⁰N/C

Step-by-step explanation:

The formula for Electric field strength is expressed as:

E = kQ/r²

k is the coulombs constant = 9*10^9Nm²/C²

Q is the charge = 1.00×10°C

r is the distance = 0.50m

Substitute the parameters into the formula as shown:

E = kQ/r²

E = 9*10^9(1)/0.5²

E = 9*10^9/0.25

E = 36*10^9

E = 3.6*10¹⁰N/C

Hence the electric field strength is 3.6*10¹⁰N/C

User Mewster
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