Question

A crate of eggs is located in the middle of the flatbed of a pickup truck as the truck negotiates a curve in the flat road. The curve may be regarded as an arc of a circle of radius 35.0 m. If the coefficient of static friction between crate and truck is 0.600, how fast can the truck be moving without the crate sliding?

Answer 1

v = 14.35 m/s

Step-by-step explanation:

As we know that crate is placed on rough bed

so here when pickup will take a turn around a circle then in that case the friction force on the crate will provide the necessary centripetal force on the crate

So here we have

`\mu mg = (mv^2)/(R)`

here we have

`\mu g = (v^2)/(R)`

now we know that

`v = √(\mu Rg)`

here we have

`\mu = 0.600`

R = 35 m

g = 9.81 m/s/s

now plug in all values in above equation

`v = √((0.600)(35)(9.81))`

`v = 14.35 m/s`