For this case we must solve the following equation:
![\sqrt {3x + 54} + 6 = 10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1zethy41lmcazw64h3vnm0tb063ii11tg8.png)
Subtracting 6 from both sides of the equation:
![\sqrt {3x + 54} = 10-6\\\sqrt {3x + 54} = 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v58oww2nxm97ndk2qr3zgzo0xnvdiae7h8.png)
We square both sides of the equation squared:
![3x + 54 = 4 ^ 2\\3x + 54 = 16](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ojwsplyk50sezezzrmn8s3m21f0i0ru5jg.png)
We subtract 54 from both sides of the equation:
![3x = 16-54](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8c6366dk83ex7tdi9e41fyepdvc8u92m50.png)
Different signs are subtracted and the sign of the major is placed:
![3x = -38](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bpuau0zr9w429785hddeqfhasco92dobj2.png)
We divide between 3 on both sides:
![x = \frac {-38} {3}\\x = - \frac {38} {3}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9oj7phv4qrbbgw0h0btlodpbr85a6ejlbx.png)
Answer:
![x = - \frac {38} {3}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kwltlogg9uyf3jodntn72tsgg5qggupd9n.png)