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What is the solution to √3x+54 + 6 = 10

User Milia
by
5.3k points

2 Answers

4 votes

Answer:

x = -(38/3)

Explanation:

Well first you have to isolate the square root on the left hand side.

Then eliminate the radical on the left hand side.

Last step

Solve the linear equation :

Rearranged equation

3x + 38 = 0

Subtract 38 from both sides

3x = -38

Divide both sides by 3

A possible solution is :

x = -(38/3)

User Moh Tarvirdi
by
5.1k points
4 votes

For this case we must solve the following equation:


\sqrt {3x + 54} + 6 = 10

Subtracting 6 from both sides of the equation:


\sqrt {3x + 54} = 10-6\\\sqrt {3x + 54} = 4

We square both sides of the equation squared:


3x + 54 = 4 ^ 2\\3x + 54 = 16

We subtract 54 from both sides of the equation:


3x = 16-54

Different signs are subtracted and the sign of the major is placed:


3x = -38

We divide between 3 on both sides:


x = \frac {-38} {3}\\x = - \frac {38} {3}

Answer:


x = - \frac {38} {3}

User Ushuz
by
5.0k points
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