Answer:
The equation in slope-intercept form is y=-2x+6.
The equation in standard form is 2x+y=6.
The equation in point-slope form is y-2=-2(x-2).
Explanation:
The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.
Parallel lines will have the same slope and different y-intercept.
Anyways the slope of y=-2x+1 is -2.
So the equation of our line we are looking for is -2.
So we know our equation is in the form y=-2x+b.
We must inf b using y=-2x+b with (x,y)=(2,2).
y=-2x +b with (x,y)=(2,2)
2=-2(2)+b
2=-4+b
Add 4 on both sides:
2+4=b
Simplify:
6=b
The equation is y=-2x+6.
Now it didn't say what form it wanted.
There are some forms I can give you like standard and point-slope form.
There is also general form but it is not too much different from standard form.
Standard form is ax+by=c where a,b, and c are integers if possible.
Point-slope form is y-y1=m(x-x1) where (x1,y1) is a point on the line and m is the slope.
So let's go for standard form (ax+by=c) first:
y=-2x+6
add 2x on both sides:
2x+y=6
This is standard form because it is in the form
ax+by=c.
Ok we know point (2,2) is on our line and we also know we have slope,m, is -2.
Point-slope form is
y-y1=m(x-x1)
y-2=-2(x-2)