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If sin theta =7/25, use the Pythagorean identity to find cos theta

1 Answer

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Answer:


\cos(\theta)=\pm (24)/(25)

Explanation:

I don't know where
\theta is so there is going to be two possibilities for cosine value, one being positive while the other is negative.

A Pythagorean Identity is
\cos^2(\theta)+\sin^2(\theta)=1.

We are given
\sin(\theta)=(7)/(25).

So we are going to input
(7)/(25) for the
sin(\theta):


\cos^2(\theta)+((7)/(25))^2=1


\cos^2(\theta)+(49)/(625)=1

Subtract 49/625 on both sides:


\cos^2(\theta)=1-(49)/(625)

Find a common denominator:


\cos^2(\theta)=(625-49)/(625)


\cos^2(\theta)=(576)/(625)

Square root both sides:


\cos(\theta)=\pm \sqrt{(576)/(625)}


\cos(\theta)=\pm (√(576))/(√(625))


\cos(\theta)=\pm (24)/(25)

User Gorf
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