Question

A sample of an ideal gas has a volume of 2.37 L at 2.80×102 K and 1.15 atm. Calculate the pressure when the volume is 1.68 L and the temperature is 304 K.

Answer 1

`p_2 = 1.76 atm`

Step-by-step explanation:

given data:

v_1 = 2.37 L

v_2 = 1.68 L

p_1 =1.15 atm

p_2 = ?

t_1 = 280 K

t_2 = 304 K

from Gas Law Equation

, WE HAVE

`(p_1 v_1)/(t_1) =(p_2 v_2)/(t_2)`

Putting the values

`(1.15*2.37)/(280)  =(p_2 *1.68)/(304)`

`9.733*10^(-3) = (p_2 *1.68)/(304)`

`9.733*10^(-3)*304 = p_2*1.68`

`(9.733*10^(-3)*304)/(1.68) =p_2`

`p_2= 1.76 atm`