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About 1% of the population has a particular genetic mutation. 700 people are randomly selected. Find the standard deviation for the number of people with the genetic mutation in such groups of 700.

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Answer: 2.632

Explanation:

Given : The probability that the population has a particular genetic mutation = 1 % = 0.01

Let X be a random variable representing the number of people with genetic mutation in a group of 700 people.

Now, X follows the binomial distribution with parameters:


n=700;\ p=0.01

The standard deviation for binomial distribution is given by :-


\sigma=√(np(1-p))\\\\=√(700*0.01(1-0.01))\\\\=2.6324893162\approx2.632

Hence, the standard deviation = 2.632

User Aghyad Algllad
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