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A container of variable volume contains oxygen gas at a pressure of 550.0 kPa. At 25.0 °C, what is the new pressure inside the container if the container is allowed to expand from an initial volume of 5.20 L to a final volume to 7.25 L

User SseLtaH
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1 Answer

3 votes

Answer:

The new pressure inside the container is 394.48 Pa.

Step-by-step explanation:

Given that,

Pressure = 550.0 kPa

Temperature = 25.0°C

Initial volume = 5.20 L

Final volume = 7.25 L

We need to calculate the new pressure inside the container

Using Boyle's law

PV = constant


P_(1)V_(1)=P_(2)V_(2)

Where, P₁ = Pressure

V₁ = Initial volume

V₂ = Initial volume

Put the volume into the formula


550*5.20=P_(2)*7.25


P_(2)=(550*5.20)/(7.25)


P_(2)=394.48\ Pa

Hence, The new pressure inside the container is 394.48 Pa.

User Multicam
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