204k views
14 votes
If the temperature of a gas increased from 100 K to 200 K and the volume of a gas decreased from 20 L to 10 L, what is the new pressure if the original pressure was kPa?

User Simon Su
by
9.0k points

1 Answer

11 votes

Answer:

320pka

Step-by-step explanation:

This is a complete question;

If the temperature of a gas increased from 100 K to 200 K and the volume of a gas decreased from 20 L to 10 L, what is the new pressure if the original pressure was 80kPa?

EXPLANATION;

Gas laws can be regarded as aws which relate the pressure, volume, as well as temperature of a gas. It can be expressed as

P1V1/T1 = P2V2/T2

Where

V1= initial volume= 20L

V2 = final volume= 10L

T1 = initial temperature= 100K

T2 = final temperature= 200K

P2=final pressure=

P1= initial pressure= 80pka

Making P2 subject of the formula from the eqn, we have

P2= (P1*V1*T2=)/(T1*V2)

If we substitute the values we have

P2= (80 × 20×200)/(100×10)

P2= 320pka

Hence, the new pressure is 320pka

User Joscelyn
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.