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he volume of a cone of radius r and height h is​ one-third the volume of a cylinder with the same radius and height. Does the surface area of a cone of radius r and height h equal​ one-third the surface area of a cylinder with the same radius and​ height? If​ not, find the correct relationship. Exclude the bases of the cone and cylinder.

User Aryann
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Answer:

The surface area of a cone of radius r and height h not equal​ to one-third the surface area of a cylinder with the same radius and​ height.

Relationship is
S_c=((√((r+h)))/(2h))S_C

Explanation:

Given : The volume of a cone of radius r and height h is​ one-third the volume of a cylinder with the same radius and height.

To find : Does the surface area of a cone of radius r and height h equal​ one-third the surface area of a cylinder with the same radius and​ height?

If​ not, find the correct relationship. Exclude the bases of the cone and cylinder.

Solution :

Radius of cone and cylinder is 'r'.

Height of cone and cylinder is 'h'.

The volume of cone is
V_c=(1)/(3)\pi r^2 h

The volume of cylinder is
V_C=\pi r^2 h


(V_c)/(V_C)=((1)/(3)\pi r^2 h)/(\pi r^2 h)


V_c=(1)/(3)V_C

i.e. volume of cone is one-third of the volume of cylinder.

Now,

Surface area of the cone is
S_c=\pi r√((r+h))

Surface area of the cylinder is
S_C=2\pi rh

Dividing both the equations,


(S_c)/(S_C)=(\pi r√((r+h)))/(2\pi rh)


(S_c)/(S_C)=(√((r+h)))/(2h)


S_c=((√((r+h)))/(2h))S_C

Which clearly means
S_c\\eq (1)/(3)S_C

i.e. The surface area of a cone of radius r and height h not equal​ to one-third the surface area of a cylinder with the same radius and​ height.

The relationship between them is


S_c=((√((r+h)))/(2h))S_C

User Nyaruko
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