Question

Suppose you calibrate a thermistor by inserting it first in ice water, then in boiling water. In ice water, the thermistor reads -45 mV and in boiling water it reads 204 mV. Next you measure the temperature of an unknown sample and read 116 mV. What is the temperature in C°?

Answer 1

Answer: The temperature of the unknown sample is 64.65 °C

Step-by-step explanation:

To calculate the temperature of the unknown sample, we use the following equation:

`T=((V-V_1))/((V_2-V_1))* (T_2-T_1)+T_1`

where,

T = temperature of the unknown sample = ?

V = thermistor reading of the unknown sample = 116 mV

`T_1` = melting point of ice = 0°C

`V_1` = thermistor reading of ice = -45 mV

`T_1` = boiling point of water = 100°C

`V_1` = thermistor reading of water = 204 mV

Putting values in above equation, we get:

`T=((116-(-45)))/((204-(-45)))* (100-0)+0\\\\T=64.65^oC`

Hence, the temperature of the unknown sample is 64.65 °C