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Through: (1,-5), perpendicular to y=18x+26

User Riju Mahna
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1 Answer

3 votes

Answer:

Explanation:

If you're asking for the equation of a line that goes through (1,-5) and is perpendicular to y=18x+26 here's what you do.

1. find the slope of the new line by taking the negative reciprocal of the slope of the first line (
-(1)/(18))

2. plug in the point (1,-5) and the new slope into the point slope form equation


y_(2) -y_(1)=m(x_(2)-x_(1))

3.Now that you have y-(-5)= -1/18(x-1) simplify

3.a y-(-5)= -1/18x + 1/18

3.b y=-1/18x - 89/18

4. final equation you get is y = -1/18 - 89/18

User Arsena
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