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Solve ABC
c=10, B=35°, C=65%​

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Answer:

Part 1) The measure of angle A is
A=80\°

Part 2) The length side of a is equal to
a=10.9\ units

Part 3) The length side of b is equal to
b=6.3\ units

Explanation:

step 1

Find the measure of angle A

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so


A+B+C=180\°

substitute the given values


A+35\°+65\°=180\°


A+100\°=180\°


A=180\°-100\°=80\°

step 2

Find the length of side a

Applying the law of sines


(a)/(sin(A))=(c)/(sin(C))

substitute the given values


(a)/(sin(80\°))=(10)/(sin(65\°))


a=(10)/(sin(65\°))(sin(80\°))


a=10.9\ units

step 3

Find the length of side b

Applying the law of sines


(b)/(sin(B))=(c)/(sin(C))

substitute the given values


(b)/(sin(35\°))=(10)/(sin(65\°))


b=(10)/(sin(65\°))(sin(35\°))


b=6.3\ units

User Rslemos
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