Question

I need help please.

In triangle ABC, A = 35°, a = 20, and b = 32. Find B. impossible to tell 21° 33° 67°

Answer 1

The measure of angle B is
`67\°`

Explanation:

we know that

Applying the law of sines

`(a)/(sin(A))=(b)/(sin(B))`

we have

`a=20\ units`

`b=32\ units`

`A=35\°`

substitute the given values and solve for B

`(20)/(sin(35\°))=(32)/(sin(B))`

`sin(B)=(32)sin(35\°)/20`

`B=arcsin((32)sin(35\°)/20)`

`B=67\°`