Answer:
z stays the same
Explanation:
We have been given that z varies directly with x and inversely with y.
Thus, we have the equation
![z=(kx)/(y)...(i)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3wjjm1h26nfv1mc2d3sljalo5ykm5s5476.png)
Here k is constant of proportionality.
Now, x and y both are doubled, thus, the equation becomes
![z=(k(2x))/(2y)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d1qqxg43j6pq0d06px3rxwufj1pd64i9v5.png)
Cancel 2 from numerator and denominator
![z=(kx)/(y)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/29h4uo9gyi7rwoe04gr20gm2ay5kxquhn8.png)
This is same as equation (i)
Hence, we can conclude that z remains same.
first option is correct.