The answer is 0.43
To calculate p we will use one of two formulas of the Hardy-Weinberg principle:
p² + 2pq + q² = 1 and p
+ q = 1
where:
p - the frequency of the allele for long legs which is a dominant trait.
q - the frequency of the allele for short legs which is a recessive trait.
p² - the frequency of dominant homozygote (with long legs)
2pq - the frequency of heterozygote (with long legs)
q² - the frequency of recessive homozygote (with short legs)
So, 33 of 100 organisms have short legs. The frequency of recessive homozygote is represented by q²:
q² = 33/100 = 0.33
⇒ q = √0.33 = 0.57
Using the formula:
p + q = 1
p = 1 - q = 1 - 0.57 = 0.43
Therefore, p = 0.43