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Which line has a slope of frac{1}{3} and goes through (3, -1)?

User Crysis
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1 Answer

1 vote

Answer:

y=1/3x - 2

Explanation:

The question asks for the equation of a line with a slope of 1/3 and passes through point (3,-1)

The equation for the line in the slope intercept form is written as y=mx+c where m is the gradient and c is the y-intercept

But you know m=Δy/Δx where Δx =x-3 and Δy=y--1


(1)/(3) =(y--1)/(x-3)

cross-multiply


(1)/(3) =(y+1)/(x-3) \\\\\\1(x-3)=3(y+1)\\\\\\x-3=3y+3\\\\-3-3=3y-x\\\\-6=3y-x\\

Divide every term by 3


-2=y-(1)/(3) x\\\\\\-2+(1)/(3) x=y

The line is


y=(1)/(3) x-2

Which line has a slope of frac{1}{3} and goes through (3, -1)?-example-1
User Ola Sundell
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