Answer:
0.68
Explanation:
Given
Mean = μ = 6 cm
SD = σ = 1.5 cm
We have to find the z-scores for 4.5 and 7.5
z-score for 4.5 = z_1 = (x-μ)/σ = (4.5-6)/1.5 = -1.5/1.5 = -1
z-score for 4.5 = z_2 = (x-μ)/σ = (7.5-6)/1.5 = 1.5/1.5 = 1
We have to find area to the left of z-scores
Using the rule of thumb for SD from mean, 68% of data lies between one standard deviation from mean. So the probability of choosing a band with length between 4.5 and 7.5 cm is 0.68 ..