Answer:
The slope of XZ is 3/4 , the slope of XY is -4/3 , and XZ = XY = 5 ⇒ 3rd answer
Explanation:
* Lets look to the attached figure to solve the problem
- To prove that the Δ XYZ is an isosceles right triangle, you must
find two sides the product of their slopes is -1 and they are equal
in lengths
- From the figure the vertices of the triangle are;
X = (1 , 3) , Y = (4 , -1) , Z = (5 , 6)
- The slope of the line whose endpoints are (x1 , y1) and (x2 , y2)
is
![m=(y_(2)-y_(1))/(x_(2)-x_(1))](https://img.qammunity.org/2020/formulas/mathematics/high-school/3fxtemrxoojbluu7ia4t5ray7mr5l0mruj.png)
∵ The slope of
![XY=(-1-3)/(4-1)=(-4)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ddk27tt0s9zhmrv96oqtt961ydtyi93vxf.png)
∵ The slope of
![XZ=(6-3)/(5-1)=(3)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mqx5mqipb01gt4hgjh5ynm7hnwyj88n3t2.png)
∴ The slope of XY = -4/3 , the slope of XZ = 3/4
∵ -4/3 × 3/4 = -1
∴ XY ⊥ XZ
∴ ∠ X is a right angle
∴ Δ XYZ is a right triangle
- The distance between the two points (x1 , y1) and (x2 , y2) is
![d=\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ujhtkf4aepvi1g2p9lnhwfcocp96l102i2.png)
∵
![XY=\sqrt{(4-1)^(2)+(-1-3)^(2)}=√(9+16)=√(25)=5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2irvnxbao5mx7uzk6om3yn7nq86ibxiz4i.png)
∵
![XZ=\sqrt{(5-1)^(2)+(6-3)^(2)}=√(16+9)=√(25)=5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qp61rvbtoq8a0o17nc7ok0u4zjjuh46e1q.png)
∴ XY = XZ = 5
∴ Δ XYZ is an isosceles right triangle
* The statement which prove that is:
The slope of XZ is 3/4 , the slope of XY is -4/3 , and XZ = XY = 5