Question

Given p(x)=3x^5+2x^2-5, what is the value of the function at -5/3

Answer 1

`-(3080)/(81)`

Explanation:

The given function is:

`p(x)=3x^(5)+2x^(2)-5`

We have to find the value of the function at x = -5/3

In order to do this we need to replace every occurrence of x in the given function by -5/3. i.e.

`p(-(5)/(3))=3(-(5)/(3))^(5)+2(-(5)/(3) )^(2)-5\\\\ p(-(5)/(3))=3(-(3125)/(243) )+2((25)/(9) )-5\\\\p(-(5)/(3))=-(3125)/(81)+(50)/(9)-5\\\\ p(-(5)/(3))=-(3080)/(81)`

Thus, the value of the function at x =-5/3 is
`-(3080)/(81)`