Answer:
15 samples
Explanation:
The total sample space consists of 6 items
{79,64,84,82,92,77}
So,
n=6
The instructor has to randomly select 2 test scores out of 6.
So, r=6
The arrangement of scores selection doesn't matter so combinations will be used.
![C(n,r)=(n!)/(r!(n-r)!) \\C(6,2)=(6!)/(2!(6-2)!)\\=(6!)/(2!*4!)\\=(6*5*4!)/(2!*4!) \\=(30)/(2)\\=15\ ways](https://img.qammunity.org/2020/formulas/mathematics/college/3qqtfz5q457x7qxry6x9spbv70elx97l9q.png)
Therefore, there are 15 different samples are possible without replacement ..