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A 900 kg car runs into a 70 kg deer at 28 m/s. If the car transfers all of its momentum to the deer, how fast does the deer go flying away?

User Blitzmann
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1 Answer

3 votes

Answer:

Mc = 900 Kg

Uc = 28 ms^-1

Md = 70 Kg

Ud = 0

We want Vd

Vc = Vd

This situation is elastic momentum


m _(c)u _(c)+ m _(d)u _(d) = m _(c)v _(c) + m _ dv _(d) \\ (900 * 28) + (70 * 0) = (900 * v _(d) ) + (70 * v _(d)) \\ 25200 = (900 + 70)v _(d) \\ 25200 = 970v _(d) \\ v _(d) = (25200)/(970) \\ v _(d) = 26 \: m {s}^( - 1)

User Nitowa
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