Question

A line passes through the point (-4,3) and has a slope of -4. Write an equation in slope-intercept form for this line. ( Please help!!!!!)

Answer 1

`\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{3})~\hspace{10em} slope = m\implies -4 \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=-4[x-(-4)]\implies y-3=-4(x+4)`

`\bf y-3=-4x-16\implies y=-4x-13\impliedby \begin{array}ll \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}`