Question

A baseball player wants to hit a home run over the wall of a stadium. He hits the ball 0.751 m above the ground with at an angle of 30 degrees above the horizontal and a speed of 37.5 m/s. What is the tallest wall the player can clear if the wall is 150 m away?

Answer 1

The baseball does not reach the wall, because the ball falls at 125.33 meters and the wall is at 150 meters

Step-by-step explanation:

V= 37.5 m/s

α= 30º

g= 9.8 m/s²

Vx= V * cos(30º) = 32.47 m/s

Vy= V * sin(30º) = 18.75 m/s

flytime of the baseball:

t= 2 * Vy/g

t= 3.86 sec

distance of baseball fall:

d= Vx * t

d= 125.33 m

Answer 2

Answer: 18.67 m wall

Explanation:this is projectile.

For Max height,

H = v²sin²©/2g

H= (37.5)²sin²(30)/(2*9.81)

H = 17.919 m

But he is standing 0.751 m above ground, so total height = 17.919+0.751= 18.67m