19.7k views
4 votes
Two resistors, of R1 = 3.93 Ω and R2 = 5.59 Ω, are connected in series to a battery with an EMF of 24.0 V and negligible internal resistance. Find the current I1 through the first resistor and the potential difference ΔV2 between the ends of the second resistor.]

User Feli
by
4.7k points

1 Answer

4 votes

Answer:

2.521 (A); 14.0924 (V)

Step-by-step explanation:

more info in the attachment, the answers are marked with red colour.

Two resistors, of R1 = 3.93 Ω and R2 = 5.59 Ω, are connected in series to a battery-example-1
User Nunzio
by
5.6k points