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The expression (27y^-2)^1/3 / y^-2/3 can be simplified and written without negative exponents as

User Carmenza
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Answer:

3

Explanation:


\displaystyle\tt \frac{(27y^(-2))^{(1)/(3)}}{y^{-(2)/(3)}}=\frac{(3^3\cdot y^(-2))^{(1)/(3)}}{y^{-(2)/(3)}}=\frac{3\cdot y^{-(2)/(3)}}{y^{-(2)/(3)}}=3

User Maxim Zagoruyko
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