Question

A man, a distance d=3~\text{m}d=3 m from a target, throws a ball at an angle \theta= 70^\circθ=70 ​∘ ​​ above the horizontal. If the initial speed of the ball is v=5~\text{m/s}v=5 m/s, what height hh does the ball strike the building?

Answer 1

The ball doesn't strike the building because it strikes the ground at d=1.62 meters.

Step-by-step explanation:

V= 5 m/s < 70º

Vx= 1.71 m/s

Vy= 4.69 m/s

h= Vy * t - g * t²/2

clearing t for the flying time of the ball:

t= 0.95 s

d= Vx * t

d= 1.62 m