Question

During the winter months, many locations experience snow and ice storms. It is a common practice to treat roadways and sidewalks with salt, such as CaCO3 . If a 11.3 kg bag of CaCO3 is used to treat the sidewalk, how many moles of CaCO3 does this bag contain?

Answer 1

The number of moles of CaCO3 on the bag is 112.90 moles

Step-by-step explanation:

number mole (n) = mass (m) divided by molecular mass (Mm)

Mm of CaCO3 = 100.0869 g/mole

mass in grams = 11.3 Kg x (10^3 g/1 Kg) = 11300 grams

number of moles (n) = 11300 grams divided by 100.0869 grams per mole = 112.90 moles of CaCO3 in the bag.