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What are the solutions of 4x2-x+9=0

User Mohoch
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1 Answer

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For this case we must find the solutions of the following equation:


4x ^ 2-x + 9 = 0

We apply the cudratic formula:


x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Where:


a = 4\\b = -1\\c = 9

Substituting:


x = \frac {- (- 1) \pm \sqrt {(- 1) ^ 2-4 (4) (9)}} {2 (4)}\\x = \frac {1 \pm \sqrt {1-144}} {8}\\x = \frac {1 \pm \sqrt {-143}} {8}

Thus, the complex roots are:


x_ {1} = \frac {1 + i \sqrt {143}} {8}\\x_ {2} = \frac {1-i \sqrt {143}} {8}

Answer:


x_ {1} = \frac {1 + i \sqrt {143}} {8}\\x_ {2} = \frac {1-i \sqrt {143}} {8}

User Sergey Kuryanov
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