Question

Write an equation of the line that passes through the point (4,-5) with slope 2 please answer

Answer 1

y = 2x - 13

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2, hence

y = 2x + c ← is the partial equation

To find c substitute (4, - 5) into the partial equation

- 5 = 8 + c ⇒ c = - 5 - 8 = - 13

y = 2x - 13 ← equation of line

Answer 2

`\huge{\boxed{y+5=2(x-4)}}`

Point-slope form is
`y-y_1=m(x-x_1)`, where
`m` is the slope of the line and
`(x_1, y_1)` is a known point on the line.

Substitute the values.
`y-(-5)=2(x-4)`

Simplify the negative subtraction.
`\boxed{y+5=2(x-4)}`

Note: This equation is in point-slope form. If you require or prefer another form, please let me know in a comment below.